Sunday, 13 November 2016

Session Four

#include<stdio.h>
void main ()
{
/* int a=10,b=20,c=30;

printf ("Enter three values \n");

scanf ("%d-%d-%d",&a,&b,&c);

printf ("First number : %d\n Second number %d \nThird number %d\n",a,b,c); */

Output : 

Enter three values 
40
First number : 40
 Second number 20 
Third number 30

Enter three values 
40&50&60
First number : 40
 Second number 20 
Third number 30

Enter three values 
ABC-5-90
First number : 10
 Second number 20 
Third number 30

Enter three values 
40-50-60
First number : 40
 Second number 50 
Third number 60



/*int a,b;

int c,d,e,f;

printf ("Enter two digits \n");

scanf ("%d %d",&a,&b);

c = a + b;
d = b - a;
e = a * b;
f = b / a;

printf ("%d + %d = %d\n",a,b,c);
printf ("%d - %d = %d\n",b,a,d);
printf ("%d * %d = %d\n",a,b,e);
printf ("%d / %d = %d\n",b,a,f);
*/

Output : 
Enter two digits 
10
20
10 + 20 = 30
20 - 10 = 10
10 * 20 = 200
20 / 10 = 2


/*int a,b;

float c,d,e,f;

printf ("Enter two digits \n");

scanf ("%d %d",&a,&b);

c = a + b;
d = b - a;
e = a * b;
f = b / a;

printf ("%d + %d = %f\n",a,b,c);
printf ("%d - %d = %f\n",b,a,d);
printf ("%d * %d = %f\n",a,b,e);
printf ("%d / %d = %f\n",b,a,f);
*/

Enter two digits 
10
20
10 + 20 = 30.000000
20 - 10 = 10.000000
10 * 20 = 200.000000
20 / 10 = 2.000000


Enter two digits 

20
10
20 + 10 = 30.000000
10 - 20 = -10.000000
20 * 10 = 200.000000
10 / 20 = 0.000000

Enter two digits 
20
10
20 + 10.000000 = 30.000000
10.000000 - 20 = -10.000000
20 * 10.000000 = 200.000000
10.000000 / 20 = 0.500000


/* int h;
float c,d,e,f,g;

printf ("Enter two digits \n");

scanf ("%d %d",&a,&b);

c = a + b;
d = b - a;
e = a * b;
f = b / a;
g = b % a;


printf ("%d + %d = %f\n",a,b,c);
printf ("%d - %d = %f\n",b,a,d);
printf ("%d * %d = %f\n",a,b,e);
printf ("%d / %d = %f\n",b,a,f);
printf ("%d MOD %d = %f\n",b,a,g); */


Enter two digits 
20
10
20 + 10 = 30.000000
10 - 20 = -10.000000
20 * 10 = 200.000000
10 / 20 = 0.000000
10 MOD 20 = 10.000000



/*
char z = 'E';
int a,b;
float c;

printf ("Enter two digits \n");

scanf ("%d %d",&a,&b);

c = z / b;

printf ("%d / %d = %f \n",z,b,c);
*/

Enter two digits 
20
10
69 / 10 = 6.000000 


/*
int a = 10;
int b=a;

printf ("%d : Value after assigning value of a\n",b);

b = ++a;

printf ("%d : Value after Post Increment\n",b);
*/

Output :
10 : Value after assigning value of a
11 : Value after Post Increment

/*
int a = 10;
int b=a;

printf ("%d : Value after assigning value of a\n",b);

b = a++;

printf ("%d : Value after Post Incrementing\n",b);
*/
Output:
10 : Value after assigning value of a
10 : Value after Post Incrementing


/* int a = 10,b=20,c=30;

int d;

d = ++a + ++b + c++ * a;

printf ("%d \n",d);
*/
Output : 362 

}

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